545B - Equidistant String - CodeForces Solution

greedy *1100

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Python Code: 

import math

s1 = input()
s2 = input()

diff = 0
for i in range(len(s1)):
    if s1[i] != s2[i]: diff+=1
    
if diff%2==1:
    print("impossible")
else:
    i = j = 0
    while i<len(s1):
        print(s1[i], end = '')
        if s1[i] != s2[i]: j+=1
        if j==diff//2: break
        i+=1
    print(s2[i+1:])

C++ Code: 

#include <iostream>
using namespace std;

string compare(string a, string b) {
    if(a > b) {
        string t = a;
        a = b;
        b = t;
    }
    int c = 0, d = a.length(), i, j;
    for(i = 0; i < d; i++)
        if (a[i] != b[i]) c++;
    if (c % 2 > 0) return "impossible";
    for(j = c, i = 0; i < d && j > c / 2; i++)
        if (a[i] != b[i]) {
            b[i] = a[i];
            j--;
        }
    return b;
}
int main() {
    string a, b;
    cin >> a >> b;
    cout << compare(a, b);
}


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